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x^2-5x=x(6+x)
We move all terms to the left:
x^2-5x-(x(6+x))=0
We add all the numbers together, and all the variables
x^2-5x-(x(x+6))=0
We calculate terms in parentheses: -(x(x+6)), so:We get rid of parentheses
x(x+6)
We multiply parentheses
x^2+6x
Back to the equation:
-(x^2+6x)
x^2-x^2-5x-6x=0
We add all the numbers together, and all the variables
-11x=0
x=0/-11
x=0
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